Light Beam - Minimum Travel Time

Calculus Level 3

A beam of light travels through a compound dielectric slab along two straight line segments from the start point to the end point, as shown. The " v v " quantities are the speeds of the light beam in the two regions.

Suppose that the light travels along a path which minimizes the total travel time. When the light gets to the boundary between the two dielectric regions, what is its x x coordinate?

Inspired by a comment from Karan Chatrath

Note: As it turns out, this is actually how light behaves within a compound dielectric slab. From this "least time" principle, we can derive various well-known optical properties.


The answer is 4.2926.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

1 3 \dfrac{1}{3} √( x 2 x^2 +1)+ 1 2 \dfrac{1}{2} √(( 6 x ) 2 6-x)^2 +4)=minimum. Therefore 5 x 4 x^4 -60 x 3 x^3 +173 x 2 x^2 -108x+324=0. The real solution to this equation less than 6 is x=4.29259

How did you construct the quartic polynomial?

Pi Han Goh - 1 year, 11 months ago

Log in to reply

Differentiate with respect to x and equate to zero

A Former Brilliant Member - 1 year, 11 months ago

Log in to reply

Got it. Thanks.

Pi Han Goh - 1 year, 11 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...