Three similar light bulbs are connected to a constant-voltage d.c. supply as shown in the diagram. Each bulb operates at normal brightness and the ammeter (of negligible resistance) registers a study current. The filament of one bulb breaks. What happens to the ammeter reading and to the brightness of the remaining bulbs?
Ammeter reading vs Bulb brightness
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As the bulbs are in parallel, when a bulb fuses, the net resistance increases. so, current decreases. Moreover, the brightness remains unchanged because they are connected in parallel. Correct me if I am wrong.