Lightning Bolt

First, you must get the charge, where We know that rate of charge flow is energy or power in $P$ = $\frac{Q}{t}$ , $Q$ is the charge, total amount of the electron and $t$ is the time. Then, you get charge by $Q$ = $P t$ = $2 C$ .

Finally, the total of electron is $n$ , $Q$ = $nq$ , where $q$ or $e$ is the element of $n$ charge, $1.6$ x $10^{-19} C$ . You must get the $n$ = $1.25$ x $10^{19}$ .

Multiplying the two quantities given shows that a total of 2C of charge are transmitted. Dividing this quantity by the charge of one electron results in the total amount of electrons that are transmitted, which is $\boxed{1.25 \cdot 10^{19}}$ electrons.

Q = It

Q = ( 20000) (100E-6) = 2 C

1 electron have 1.6E-19 C

Number of electrons = (1/1.6E-19) (2) = 1.25E19

If $n$ is the number of flowing electrons in $100 μs = 100 \times 10^{-6} s$ ; $\frac {Q}{t} = 20 \times 10^3$ $\Rightarrow \frac {n\times1.6 \times 10^{-19}}{100 \times 10^{-6} } = 20 \times 10^3$ $\Rightarrow n=1.25 \times 10^{19}$

As $100 μs=10^{-4}s$ , every lightning bolt has a charge flow of $2 \times 10^{4} \times 10^{-4} C$ . To calculate how many electrons flow between the ground and the cloud during one lightning bolt,we take the charge flow of the lightning bolt and divide it by the charge of the electron. So,we have $\frac {2 \times 10^{0}}{1.6 \times 10^{-19}}$ which is $1.25 \times 10^{19}$ .

To find the total charge, we divide the rate of charge flow with the time;so we get 2 coulombs. Then we divide the total charge with the charge of one electron to find the number of the electrons. Thus we get 0.125×10^20 or 1.25E+19 electrons.

First of all, we are given that charge flow per second is 20kC and and charge flows for 100μs. So, from here we calculate the total charge that flowed, using the fact that 1μs=1E-6s. So, 100μs means 1E-4seconds. Therefore, the total charge that flowed is 20000*1E-4 which is 2C. Now, we are given that charge on 1 electron is 1.6E-19C, so the total number of electrons that flowed is 2/(1.6E-19) = 1.25E+19.