Lim...it.

Calculus Level 3

Consider a non-zero function f : R R f: \mathbb {R \to R} such that lim x f ( x y ) x 3 \displaystyle \lim_{x \to \infty} \frac {f(xy)}{x^3} exists for all y > 0 y>0 . Let g ( y ) = lim x f ( x y ) x 3 \displaystyle g(y) = \lim_{x \to \infty} \frac {f(xy)}{x^3} . If g ( 1 ) = 1 g(1)=1 , find the value of g ( 4 ) g(4) .


The answer is 64.

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1 solution

If the limit exists . g(y) has to be y^3. It is a very intuitive solution and I do not think further explanation would be necessary.

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