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( n 2 + 0 ) 8 1 − ( n + 1 ) 4 1 n 4 1 − ( n + 1 ) 4 1 < ( n 2 + 1 ) 8 1 − ( n + 1 ) 4 1 < ( n 2 + 2 n + 1 ) 8 1 − ( n + 1 ) 4 1 < ( n 2 + 1 ) 8 1 − ( n + 1 ) 4 1 < ( n + 1 ) 4 1 − ( n + 1 ) 4 1
Since the right-hand side is zero for all n , and the left-hand side tends to zero as n → ∞ , by the squeeze theorem
n → ∞ lim ( n 2 + 1 ) 8 1 − ( n + 1 ) 4 1 = 0