Limits on cosine!

Calculus Level 3

lim n cos ( π n 2 + n ) \large \lim_{n\to \infty} \cos \left ( \pi \sqrt{n^2+ n} \right)

Calculate the limit above for integer n n .


The answer is 0.

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1 solution

Haroun Meghaichi
Aug 26, 2014

Note that for n > 0 n>0 : n 2 + n = n 1 + 1 n = n ( 1 + 1 2 n + o ( 1 n ) ) = n + 1 2 + o ( 1 ) \sqrt{n^2+n} = n\sqrt{1+\frac{1}{n} } = n\left(1+\frac{1}{2n} + o\left(\frac{1}{n}\right) \right)= n+\frac{1}{2} +o(1) The limit is clearly lim n cos ( n π + π 2 + o ( 1 ) ) = 0 \displaystyle \lim_{n\to \infty} \cos \left(n\pi +\frac{\pi}{2}+o(1)\right) =0 .

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