n → ∞ lim ∫ 0 n π e − x ∣ sin ( x ) ∣ d x
If the limit above can be expressed as α ( 1 − e λ 1 + e β ) where α , β , λ are real numbers, α ≥ 0 and β , λ ≤ 0 and n is an integer, find the value of 2 ( α + β − λ ) .
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Edit the question because,
2 1 ( 1 − e − π ) ( 1 + e − π ) = 2 − 1 ( 1 − e π ) ( 1 + e π )
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Thanks for informing me. I never noticed it :/
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