Limit of a Definite Integral 3

Calculus Level 5

lim n 0 n π e x sin ( x ) d x \large \lim_{n\to\infty} \int_0^{n\pi} e^{-x} |\sin(x)| \, dx

If the limit above can be expressed as α ( 1 + e β 1 e λ ) \alpha \left( \frac{1+e^\beta}{1-e^\lambda} \right) where α , β , λ \alpha, \beta, \lambda are real numbers, α 0 \alpha \geq 0 and β , λ 0 \beta, \lambda \leq 0 and n n is an integer, find the value of 2 ( α + β λ ) 2(\alpha+\beta-\lambda) .


The answer is 1.

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1 solution

Satyajit Mohanty
Jul 13, 2015

Edit the question because,

1 2 ( 1 + e π ) ( 1 e π ) = 1 2 ( 1 + e π ) ( 1 e π ) \cfrac { 1 }{ 2 } \cfrac { \left( 1+{ e }^{ -\pi } \right) }{ \left( 1-{ e }^{ -\pi } \right) } =\cfrac { -1 }{ 2 } \cfrac { \left( 1+{ e }^{ \pi } \right) }{ \left( 1-{ e }^{ \pi } \right) }

Ayush Verma - 5 years, 10 months ago

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Thanks for informing me. I never noticed it :/

Satyajit Mohanty - 5 years, 10 months ago

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