Limit of a sequence

Calculus Level 2

$\large \lim_{n\to\infty} \dfrac{\sqrt[n]n}n = \, ?$

\infty

0 1 impossible to determine e

1 solution

Rishabh Deep Singh
Jan 25, 2016

$y=\lim _{ n\rightarrow \infty }{ \frac { 1 }{ { n }^{ \left( 1-\frac { 1 }{ n } \right) } } } \quad \quad \quad \quad \quad \quad \left( \frac { 1 }{ { \infty }^{ 1 } } \right) \\ (not\quad an\quad indeterminant\quad form)\\ y=\frac { 1 }{ { \infty } } =0$

Moderator note:

This solution is wrong. You cannot selectively apply limits at various parts of the function.

IE $\lim f(x) ^ { g(x) }$ need not equal to $\lim f(x) ^ { \lim g(x) }$ .

This solution is wrong. You cannot selectively apply limits at various parts of the function.

IE $\lim f(x) ^ { g(x) }$ need not equal to $\lim f(x) ^ { \lim g(x) }$ .

Calvin Lin Staff - 5 years, 4 months ago

This is completely wrong, view list of common misconceptions the infinity part.

Aareyan Manzoor - 5 years, 4 months ago

Limit of a sequence

1 solution

Moderator note:

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