What is the limit of the function as "x" approaches infinity ?
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How did you directly evaluate
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Observe that this is equivalent to lim x → ∞ x x lim x → ∞ 1 . We know that x x = x 1 / x = e x ln x . Since, ln x grows slower than x , x x = 1 as x goes to infinity. Hence, the original limit goes to 1 as well.
Another possible way to evaluate this is rewriting the limit using the substitution m = x 1 as, m → 0 lim ( m m ) If you evaluate it now, the value comes out as 0 0 which is taken as 1 most of the time but that isn't true for all cases and the value is undefined! Checking the limit by substituting values of x like x = 0 . 0 0 0 0 1 gives us a result tending to 1 . So, the value of the limit is 1 . This concludes the solution.
This looks to be the most comprehensive one.
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x → ∞ lim x x 1 1 = ∞ ∞ 1 1 = ∞ 0 1 = 1 1 = 1