Limitless

Calculus Level 2

$\large \lim_{x \to \infty}\left( \frac{2 \sin^2(x)}{\sqrt{x}}\right) =\, ?$

The answer is 0.

by A Former Brilliant Member

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Deepak Kumar
Jul 1, 2016

Numerator is a finite quantity.hence limit=0

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...