Don't Overthink It!

Calculus Level 2

What is the value of lim x 4 f ( x ) \lim_{x \to 4} f(x)

If f ( x ) = { x + 3 x 2 if x < 2 , and 5 < x 1 2 × x + 2 if 2 x 5 for x 4 20 if x = 4. f(x) = \begin{cases} |x+3-x^2| & \text{if } -\infty \leq x < 2 , \text{and }5<x \leq \infty\\\frac {1}{2} \times |x| +2 & \text{if } 2 \leq x \leq 5 \text{ for } x \neq 4\\20 & \text{if } x=4. \end{cases}


The answer is 4.

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1 solution

Kay Xspre
Oct 27, 2015

4 is in the interval of 2 x 5 2 \leq x \leq 5 , hence it will fall under f ( x ) = 2 + x 2 f(x) = 2+\frac{|x|}{2} , but this is not defined at x = 4 x = 4 as f ( 4 ) = 20 f(4) = 20 . We need to find the limit when x x approaches 4, so we have to use two-handed limit.

In this case, 0 < 2 x 5 0 < 2 \leq x \leq 5 , then x > 0 x > 0 , so we can remove the absolute value and the two-handed limit will remain the same. We just find the limit of the given expression, which gives: lim x 4 ( 2 + x 2 ) = 2 + 2 = 4 \lim_{x\rightarrow4}(2+\frac{x}{2}) = 2+2 = 4

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