Evil Limiting Function

Calculus Level 4

Suppose we define f ( x ) = sgn ( sin ( x ) ) + { x } f(x) = \text{sgn}(\sin(x)) + \{ x\} for 2 x 4 2\leq x\leq4 and g ( x ) = 2 + x 3 g(x) = -2 +|x-3| , find the value of lim x 3 g f ( x ) \displaystyle \lim_{x\to3} g\circ f(x) .

Notations

  • sgn ( x ) \text{sgn}(x) denotes the signum function of x x , sgn ( x ) = { 1 , x > 0 0 , x = 0 1 , x < 0 \text{sgn}(x) = \begin{cases} 1 \quad,\quad x>0 \\ 0 \quad,\quad x=0 \\ -1 \quad,\quad x<0 \end{cases} .

  • { x } \{ x\} denote the fractional part of x x , { x } = x x \{x\} = x - \lfloor x\rfloor .

  • g f ( x ) = g ( f ( x ) ) g\circ f(x) = g(f(x)) .


-1 1 0 2 Does not exist

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1 solution

Piyush Parwani
Sep 10, 2015

The left hand limit evaluates to - 1 and the right hand limit evaluates to 0, therefore limit does not exist

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