Limits of Function

Calculus Level 2

lim x 2 x 2 4 x 5 + 6 x = ? \lim_{x\to2} \dfrac{x^2-4}{x - 5 + \frac6x} = \, ?

6 -7 -8 9

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2 solutions

Lu Chee Ket
Feb 10, 2015

x (x - 2)(x + 2)/ [(x - 2)(x -3)] --> x (x + 2)/ (x - 3) = 2 (4)/ (-1) = -8

Krunal Deshmukh
Feb 9, 2015

L' Hospital rule.

Not really.

Lu Chee Ket - 6 years, 4 months ago

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lim┬(x→2)⁡〖(x^2-4)/(x-5+6/x)〗

Here, x→2 Therefore, this limits are 0/0 form Then L’ Hospital rule

lim┬(x→2)⁡〖2x/(1+(6× (-1)/x^2 ))〗 4/(1-6/4) then ans is = (-8 )

Krunal Deshmukh - 6 years, 4 months ago

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You are right. This is fast. The thing I mean is not to an extend that we must apply differentiation as the only way for this question. Nevertheless, this approach is ultimate compared to what I had written above.

Lu Chee Ket - 6 years, 4 months ago

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