Limits9

Calculus Level 3

Find lim x 0 x sin x x tan x \displaystyle\lim_{x \rightarrow 0} \displaystyle\frac{x -\sin x}{x- \tan x} .

4 9 \frac{4}{9} 1 2 \frac{1}{2} 1 7 \frac{-1}{7} 1 2 \frac{-1}{2}

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1 solution

Anurag Pandey
May 7, 2015

There are many methods to solve the problem: 1. Using series expansion of sin x and tan x

  1. By L'Hospitals rule

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