Find , where:
where is the square of vertices , , , , and .
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i --> j
Singularities z = (1 + j 0), (-1 + j 0), (0 + j) and (0 - j) are NOT enclosed by C as described, although (z^4 - 1)^n of n = 1 satisfied. (2 + j 2) is a center for rough idea.
Basically, I think those with answer j n 2 Pi i.e. j 2 Pi arise due to the fact of 2 Pi which is duplicated for zero. Otherwise, all of those coming back are just like 1 to -1 and back to 1 again in real which ought to be zero only. When angle system in degrees only valid with 0 to 360- or -180- to 180 but no greater or equals to 360, any integration coming back must only be zero. Something to do with our perspective. Nevertheless, those not enclosed are raising no doubt to contour integrals.
The answer is certainly 0.