Consider the following curve, where the coordinates of each point on the curve are ( x , y , z ) :
x = cos θ sin ϕ y = sin θ sin ϕ z = cos ϕ θ = α ϕ = 2 π − α 0 ≤ α ≤ 2 π
There is also a vector field present at all points in space:
F = ( F x , F y , F z ) = ( x , y 2 , z 3 )
What is the absolute value of the line integral of the vector field over the curve?
∣ ∣ ∣ ∫ C F ⋅ d ℓ ∣ ∣ ∣ = ?
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Greetings from Grenada, Steven!
The path runs from A ( 1 , 0 , 0 ) to B ( 0 , 0 , 1 ) , and F has a potential f ( x , y , z ) = 2 x 2 + 3 y 3 + 4 z 4 so the line integral is f ( B ) − f ( A ) = − 4 1 and the answer is 0 . 2 5 .