Linear function - iii

Algebra Level 2

The function $f(x) = mx +c$ satisfies the following $f(f(f(0))) = 28$ and $f(f(f(1))) = 36$ .

What is the value of $f(1007)$ ?

1 solution

Oliver Papillo
Jan 25, 2018

$m(m(c)+c)+c = 28$

$m(m(m+c)+c)+c = 36$

So $m^3=8$ , $m = 2$

$2(2(c)+c)+c = 7c = 28$ , $c = 4$

$f(1007) = 2(1007)+4 = 2018$