Linear System of Differential Equations

Calculus Level 2

x ˙ 1 = x 1 x 2 \dot{x}_1 = -x_1 - x_2 x ˙ 2 = x 1 x 2 \dot{x}_2 = x_1 - x_2

Here x 1 x_1 and x 2 x_2 are functions of time t t . What happens to the solutions x 1 ( t ) x_1(t) and x 2 ( t ) x_2(t) (subject to any initial conditions) after a very long time?

Bonus: Attempt to derive a general relation between x 1 x_1 and x 2 x_2 which is independent of time.

They converge to a non zero value They converge to zero Cannot Say The solutions diverge towards infinity

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2 solutions

Steven Chase
Sep 5, 2019

The system has the form:

x ˙ = A x \dot{x} = A x

The solutions therefore take the form:

x = c 1 e λ 1 t v 1 + c 2 e λ 2 t v 2 x = c_1 e^{\lambda_1 t} \vec{v}_1 + c_2 e^{\lambda_2 t} \vec{v}_2

In the above equation, the λ \lambda values are the eigenvalues of the matrix A A , and the v \vec{v} vectors are the eigenvectors.

As it turns out, the eigenvalues of the matrix are complex, with negative real parts. So the solutions are oscillatory, but their envelopes tend toward zero.

Solving the given two differential equations, we get d 2 x 2 d t 2 + \dfrac{d^2x_2}{dt^2}+ 2 d x 2 d t + 2\dfrac{dx_2}{dt}+ 2 x 2 = 0 2x_2=0 and a similar equation for x 1 x_1 . So x 2 x_2 decays exponentially with time and so also x 1 x_1 .

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