Linear System

Algebra Level 3

Check the option that identifies the locus of all ordered pairs (a, b) ∈ R² that make the linear system impossible

S : { x + 5 y = 10 ( a 2 5 + 5 b 2 ) x + 10 a b y = 1 S :\left\{\begin{array}{l}{-x+5 y=10} \\ {\left(\frac{a^{2}}{5}+5 b^{2}\right) x+10 a b y=1}\end{array}\right.

A hyperbole A parable An ellipse A line

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Δrchish Ray
Jul 21, 2019

In order for the system of the equations to be unsolvable, the ratios of the coefficients of x x and y y must be the same in each equation. For example:

{ 3 x + 5 y = 10 6 x + 10 y = 14 \begin{cases} 3x + 5y = 10 \\ 6x + 10y = 14 \end{cases}

Therefore, 10 a b a 2 5 + 5 b 2 = 5 1 \displaystyle \frac{10ab}{ \frac{ a^{2} }{5} + 5b^{2}} = \frac{5}{-1}

10 a b = ( 5 ) ( a 2 5 + 5 b 2 ) \displaystyle \Longrightarrow 10ab = (-5)(\frac{ a^{2} }{5} + 5b^{2})

10 a b = a 2 25 b 2 \displaystyle \Longrightarrow 10ab = -a^{2} - 25b^{2}

10 a b = a 2 25 b 2 \displaystyle \Longrightarrow 10ab = -a^{2} - 25b^{2}

10 a b + a 2 + 25 b 2 = 0 \displaystyle \Longrightarrow 10ab + a^{2} + 25b^{2} = 0

( a + 5 b ) 2 = 0 \displaystyle \Longrightarrow (a+5b)^{2} = 0

a + 5 b = 0 \displaystyle \Longrightarrow a+5b = 0

a = 5 b \displaystyle \Longrightarrow a = -5b

The final equation gives us that the relationship between a a and b b is linear, and thus the graph will form a line \fbox{line} .

There are lots of spelling mistakes. (I) parabola (ii) hyperbola. Also, simply a line is not enough. Lines can be straight or curved. The correct option should be a straight line.

Euclid defined the word line to be a straight line. The person may not speak English well and/or autocorrect may be to blame for the misspellings, though they do not take away anything from the problem.

But just report the problem instead of posting a solution.

Δrchish Ray - 1 year, 10 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...