Check the option that identifies the locus of all ordered pairs (a, b) ∈ R² that make the linear system impossible
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In order for the system of the equations to be unsolvable, the ratios of the coefficients of x and y must be the same in each equation. For example:
{ 3 x + 5 y = 1 0 6 x + 1 0 y = 1 4
Therefore, 5 a 2 + 5 b 2 1 0 a b = − 1 5
⟹ 1 0 a b = ( − 5 ) ( 5 a 2 + 5 b 2 )
⟹ 1 0 a b = − a 2 − 2 5 b 2
⟹ 1 0 a b = − a 2 − 2 5 b 2
⟹ 1 0 a b + a 2 + 2 5 b 2 = 0
⟹ ( a + 5 b ) 2 = 0
⟹ a + 5 b = 0
⟹ a = − 5 b
The final equation gives us that the relationship between a and b is linear, and thus the graph will form a l i n e .