Linearize the Trigonometric Powers Part 1

Geometry Level 1

cos 2 θ = a 2 cos ( 2 θ ) + a 0 \cos^2 \theta = a_2 \cos (2 \theta) + a_0

Above shows a trigonometric identity for constants a 0 , a 2 a_0, a_2 .

What is the value of a 0 + a 2 a_0 + a_2 ?

See Part 2 , Part 3 , and Part 4 .


The answer is 1.

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1 solution

Jake Lai
May 6, 2015

We rearrange the identity cos 2 θ = 2 cos 2 θ 1 \cos 2\theta = 2\cos^{2} \theta -1 as

cos 2 θ = 1 2 cos 2 θ + 1 2 \cos^{2} \theta = \frac{1}{2} \cos 2\theta + \frac{1}{2}

It can be seen that a 0 = a 2 = 1 2 a_{0} = a_{2} = \frac{1}{2} . Hence, a 0 + a 2 = 1 a_{0}+a_{2} = \boxed{1} .

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