Lines perpendicular to the diagonals of a rectangle with side lengths 2 and 6 are drawn through the rectangle's vertices. What is the area of the quadrilateral formed by the intersection of the lines truncated to the tenth place? ex. If it was 600.8986... make it 600.8
Note: Figure is not to scale.
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We can see that △ A G O ≡ △ E A O ≡ △ A O F are similar right-angle triangles.
We note that: A O = O G 2 + G A 2 = 1 2 + 3 2 = 1 0 .
⇒ O E = 1 0 A O = ( 1 0 ) 2 = 1 0
⇒ E F = 3 1 0 O E = 1 0 3 1 0
Area of the quadrilateral = E F × A C = E F × 2 × A O = 1 0 3 1 0 × 2 × 1 0 = 3 2 0 0 ≈ 6 6 . 6