Lines In The Square

Geometry Level 5

Find the sums of the length of P C \overline{PC} and the area of the square A B C D ABCD containing a point P P such that P A = 3 PA = 3 , P B = 7 PB =7 , and P D = 5 PD=5 .

Given the answers to 4 decimal places.


The answer is 66.0623.

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1 solution

Ahmad Saad
Mar 13, 2017

In the second line of your solution, how did you get s i n θ = a 2 + 9 49 6 a sin\theta = \frac{a^2 + 9 - 49}{6a}

A Former Brilliant Member - 4 years, 2 months ago

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<BAP = 90 - θ ---> cos(BAP) = sinθ

Using cosine law for Tr.BAP

7^2 = a^2 + 3^2 - 2 3 a cos(BAP) = a^2 + 9 - 6a*sinθ

sinθ = [ a^2 + 9 - 49 ] / 6a

Ahmad Saad - 4 years, 2 months ago

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