Consider a spherical planet with radius made of a liquid with density . Find the pressure in the center of the planet, in N/m .
Details and assumptions
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First, let's determine the gravitational find at a generic distance r from the center.
"Gauss's Law" for gravitation
∫ g ⋅ d A = 4 π G M e n c l o s e d
Consider a concentric sphere with the planet (radius r, r<R) as our gaussian surface. "g" will be a constant along our integral, so itleaves the integral and we are left with an area integral(the surface area of the inner sphere).Then:
g 4 π r ² = 4 π G M R ³ r ³ g = G M R ³ r
Now that we have g, let's try to adapt P = ρ g h for this variable g situation. Consider a tiny column of liquid, with height dh exerting a pressure dP
d P = ρ g d h = ρ g d r
Pluggin the g we found and integrating both sides, we get: d P = ρ G M R ³ r d r P = R ³ ρ G M ∫ 0 R r d r = 2 R ρ G M Doing the math, P = 5 . 2 E 4