$ln$

Algebra Level 1

If $\ln(a) = b$ and $\ln\left( \dfrac1a \right) = k \times b$ , find $k$ with $a\in \mathbb{R}^+$

The answer is -1.

1 solution

Isaac Reid
Feb 4, 2016

$ln(a)=b$

$-ln(a)=-b$

$ln(a^{-1})=-b$

$ln(\frac{1}{a})=-b$

So $k=-1$ .

You can use $\ln\left(a\right)$ to make the logarithms look better.

Jesse Nieminen - 4 years, 9 months ago