Suppose a real number
satisfy the inequality
and
is an even number, find the value of
.
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8 2 1 < A < 8 2 2 ⟹ 2 6 3 < A < 2 6 6
Taking log of base 2 both sides we get
6 3 < lo g 2 A < 6 6
(Note: base>1 so inequality remains same)
Since l o g 2 A is even and the only even number between 6 3 and 6 6 is 6 4 it follows that
l o g 2 A = 6 4
A = 2 6 4 = 4 3 2
l o g 4 A = 3 2