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Algebra Level 2

Given that log 10 2016 = 3.3044 \text{Given that } \log_{10}{2016}=3.3044 What is log 10 ( 2.016 × 1 0 2016 ) ? \text{What is } \log_{10}{ \left(2.016 \times 10^{2016} \right) } \, ?


The answer is 2016.3044.

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1 solution

Rishabh Jain
Feb 21, 2016

log ( A × B ) = log A + log B \large \log (A\times B)=\log A +\log B log 10 ( 2.016 × 1 0 2016 ) \Large \therefore \log_{10}{ (2.016 \times 10^{2016} )} = log 10 ( 2016 × 1 0 2013 ) \Large = \log_{10}{ (2016 \times 10^{2013} )} = log 10 2016 + log 10 1 0 2013 \Large =\log_{10}{2016}+\log_{10}{10^{2013} } = 3.3044 + 2013 \Large =3.3044+2013 = 2016.3044 \huge =\boxed{\color{#3D99F6}{2016.3044}}

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