log(a) vs. log(t)

Figure shows the plot of time vs. acceleration on a log-log scale, for a body in a straight line motion, starting from rest at the origin. The displacement (in units) at the end of t=2 sec. is { θ = t a n 1 ( 1 / 2 ) \theta = tan^{-1}(1/2) } The coordinates of point A are (0, l o g 6 2 \frac{-log6}{2} )


The answer is 8.

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