Logarithm #2.

My proof.

$\log_a{b=c}$ . For find $\large{a}$ we prove it $\sqrt[c]{b}={a}$ .

then $\sqrt[4]{20736}$ $\large{=}$ $\large{a_1=12}$ .

$\sqrt[3]{42875}$ $\large{=}$ $\large{a_2=35}$ .

$\large{(2018×12)}$ $\large=24216-35=24181$ .

$\large{Note=}$ $\large{a_1}$ is $\large{b}$ in problem.