logarithm

Level 2

e^xlnx =??

e^x x x^x e^e

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1 solution

Rahul Kairamkonda
Oct 11, 2014

By using simple logarithmic properties

Step1: for any equation e^ln(f(x)) is always = f(x)

Step2: xlnx= ln(x^x) by property

Therefore the solutions for this answer is x^x

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