Logarithm - Basics Part II

Algebra Level 3

$\huge \color{#20A900}{log_eabc-log_e|c|=?}$ $\text{Choose the right option : }$

A. $log_e|a|+log_e|b|$

B. $-log_e|a|-log_e|b|$

C. $log_ea+log_eb$

D. $log_ea+log_e|b|$

E. $log_e|a|+log_eb$

E B C A D

1 solution

Ravesh Kumar
Jul 2, 2015

log is defined for the positive real number. so, lnabc - ln mod(c)=ln (abc) /ln mod(c)= ln mod(a)+ ln mod(b).