Find the crossing points of and
Give your answer in the form of
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The two equations combined yields x × 4 x = 3 2 . Since for negative x the value of the L. H. S. is negative, the curve y = x × 4 x can not intersect the line y = 3 2 . For positive x , the function y = x × 4 x is increasing and at x = 0 , y = 0 < 3 2 . Hence it will intersect the line y = 3 2 only once in this domain. This will happen when x = 2 , and hence y = 5 − 2 x = 1 .
So x + y = 2 + 1 = 3 .