The general formula for this one is: $\log_x{(a)}-\log_x{(b)}=\log_x{({ a }\div{ b })}$ Therefore, inputting our values: $\log_5{(65)}-\log_5{(13)}=\log_5{({65}\div{13})}$ $\log_5{(65\div13)}=\boxed {log_5{(5})}$ Although this is the answer required, we can simplify this further by utilising the rule: $\log_x{x}=1$ So: $\log_5{5} = 1$ The Log subtraction rule is important to remember!

(Log 65 to the base 5)-log(13 to the base 5) =log((65/13)to the base 5) =log(5 To the base 5)