Logarithms

Algebra Level 2

What is 'x' ?

-3, 4 4, 3 2, 4 3, -4

Anirudh Srinivas by Anirudh Srinivas , 20, India

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2 solutions

log ⁡ 2 [ log ⁡ 7 ( x 2 − x + 37 ) ] = 1 ⇒ log ⁡ 7 ( x 2 − x + 37 ) = 2 \log_2{[\log_7{(x^2-x+37)}]} = 1\quad \Rightarrow \log_7{(x^2-x+37)} = 2

⇒ x 2 − x + 37 = 49 ⇒ x 2 − x − 12 = 0 \Rightarrow x^2-x+37 = 49\quad \Rightarrow x^2-x-12 = 0

⇒ ( x + 3 ) ( x − 4 ) = 0 ⇒ x = − 3 , 4 \Rightarrow (x+3)(x-4) = 0 \quad \Rightarrow x = \boxed{-3, 4}

2 Helpful 0 Interesting 0 Brilliant 0 Confused
Prt Agr
Sep 7, 2014

x^2 -x +37=49.. solve to get 4, -3.

0 Helpful 0 Interesting 0 Brilliant 0 Confused

First you have to explain how you get this-

Krishna Ar - 6 years, 9 months ago

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