Logarithm Exponents

Algebra Level 1

Knowing that log ( 4 ) = 0.602 \log(4) = 0.602 , evaluate log ( 256 ) \log(256) .

No Calculators allowed!


The answer is 2.408.

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4 solutions

Stewart Feasby
Oct 9, 2014

Simple, knowing: l o g ( 4 ) = 0.602 log(4) = 0.602 Then as 256 = 4 4 256=4^4 l o g ( 256 ) = l o g ( 4 4 ) log(256) = log(4^4) l o g ( 4 4 ) = 4 × l o g ( 4 ) log(4^4) = 4\times log(4) 4 × 0.602 = 2.408 4\times 0.602 = \boxed {2.408} Simple logarithmic manipulation using the rule: l o g ( a b ) = b × l o g ( a ) log(a^b) = b\times log(a)

Good solution,did by the same method.

Anuj Shikarkhane - 6 years, 8 months ago
Adit Sawant
Apr 18, 2015

Me too, the same method

Adrianne Galvez
Feb 17, 2015

so log(4) = 0.602 then log (256) is also equal to log (4)^4

by properties of logarithm log(4)^4 can also be written as 4log(4)

then we input the value of log(4)=0.602 to 4log(4)

4(0.602) = 2.408 :)

Shailesh Kumar
Oct 11, 2014

Log (2)=0.301

log (256)=log(2)^8=8 log (2)=2.408

Yes, although it's long winded. No need to go from log(4) to log(2). Good method though!

Stewart Feasby - 6 years, 8 months ago

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