Logarithms' challenger #5

Algebra Level 2

If 4 A + 9 B = 1 0 C 4^{A}+9^{B}=10^{C} where A = log 16 4 , B = log 3 9 A=\log_{16}{4},B=\log_{3}{9} and C = log x 83 C=\log_{x}{83} ,Then find x x .


This problem is a part of this set .


The answer is 10.

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1 solution

Swapnil Das
May 19, 2016

A = log 16 4 = 1 2 B = log 3 9 = 2 A=\log _{ 16 }{ 4 } =\frac { 1 }{ 2 } \\ B=\log _{ 3 }{ 9 } =2

4 1 / 2 + 9 2 = 10 log x 83 \Rightarrow { 4 }^{ 1/2 }+{ 9 }^{ 2 }={ 10 }^{ \log _{ x }{ 83 } }

\Rightarrow 2+81={ 83 }^{ \log _{ x }{ 10 } }\\ \Rightarrow \color\red{x=10}

N I C E \mathcal{NICE}

Rohit Udaiwal - 5 years ago

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