Logarithms Question 1

Thank you for solving

For $\log_x(y^3)= 2$ we get that $\log_x(y) = \frac{2}{3}$ . As $\log_x(y) = \frac{1}{\log_y(x)}$ , we then get $\log_y(x) = \frac{3}{2}$ , and then $\log_y(x^4) = 4\log_y(x) = 4(\frac{3}{2}) = 6$