Logging the logs

Algebra Level 4

f ( x ) = log 4 log 5 log 3 ( 18 x x 2 77 ) \large f(x) = \log_4 \log_5 \log_3 (18x-x^2-77)

What is the integral value of x x for which the function above has a finite value?


The answer is 9.

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1 solution

To shorten out our choices, we will first consider the domain of the first logarithm.

18 x x 2 77 > 0 x ( 7 , 11 ) 18x-x^2-77 > 0 \Rightarrow x \in (7,11)

The integer values in the above set of values of x x are 8,9,10 .

On substituting 8 and 10, the first logarithm equals 0, which makes the second logarithm undefined.

On substituting 9, the first logarithm is greater than 1, i.e., l o g 3 4 log_34 .

The second logarithm is also defined and non negative since for the second logarithm to be negative the values should be 0.2 \leq 0.2 .

So 9 is the answer.

Moderator note:

It's just as simple as that!

Bonus question : Is there any solution if the function is replaced as f ( x ) = log 6 log 4 log 5 log 3 ( 18 x x 2 77 ) f(x) = \log_6 \log_4 \log_5 \log_3 (18x-x^2-77) instead?

In reply to the Moderator, No there is no integral solution.......

In fact, there is no real x which satisfies the given equation.....

Aaghaz Mahajan - 3 years, 2 months ago

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