If 1 1 1 1 = R, 2 2 2 2 = T, 3 3 3 3 = E, 4 4 4 4 = N, then 5 5 5 5 = ?
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Given, 1 1 1 1 = R. By adding we get: 1+1+1+1 = 4. In words we have, FOUR where the answer R is the last alphabet of the word. Similarly, 2+2+2+2 = 8. In words we have, EIGHT where the answer T is the last alphabet of the word. So, we get: 3+3+3+3 =E ; 4+4+4+4 = N & 5+5+5+5 = 20(TWENTY) which gives Y as the answer.