What is the minimum number of basic one/two input gates needed to implement the following Boolean Function?
F ( w , x , y , z ) = w ′ x ′ y ′ z ′ + w x ′ y z ′ + x ′ y ′ z ′ + w ′ x ′ z ′ + w x z + x y ′ z + w ′ x z
Clarifications:
As an explicit example,
For the function F ( x , y , z ) = x y ′ z + x y ′ z ′ + x ′ y ′ , this can be simplified to be F ( x , y , z ) = y ′ , which means it only needs one NOT gate to have the function implemented.
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