Logic supports math

If we take the general principle square root value of $2209$ , then we get --->

$\sqrt{2209}=47$

Now, since $47$ is a prime number, so only $1$ and the no. itself, i.e., $47$ are its factors.

So, sum of factors $=47+1=\boxed{48}$

$N=\sqrt{2209}=47$ The only factors of $47$ are $1$ and $47$ And $47+1=\boxed{48}$

The only factors of 47 are 1 and itself as it is a prime number. So, the answer is 48

Squire root of 2209 is 47 ,it's faqctors are 47 and 1,when we add answer is 48. K.K.GARG,India

Extract the square root of 2209, which results to 47. The prime factors of 47 includes 47 and 1 (identity property of multiplication) Add the factors 47 + 1 = 48

Square root of 2209 is 47, whose factors are 1 & 47. The sum of factors is 1+47=48

Ans:-48 x=2209^(1/2) x=47 is a prime no. sum=47+1=48

the no is =x. x=(2209)^1/2 u will get 47. now the factor of 47 is=47*1. so sum of its factor =47+1=48

sqrt(2209)=47, factors of 2209=1, 47, sum of two factors= 1+47=48, answer=48

\sqrt { 2209 } = 47 Factors of 47= 1,47 Sum of factors = 1+47 = 48

As 47 is a prime number, add it by one.