Logical Number Search 2

A positive Walk conveys addition with count W = +1 and a positive Jump conveys addition with count J = +2 . A negative Walk conveys subtraction with count W = - 1 and negative Jump conveys subtraction with count J = - 2 . The ' Count Exclusion ' is a process that takes place a values obtained by W and J from selected value .

Example : From a negative integer - 19 , a positive Walk imparts (-19) + W = ( -18) and a negative Walk imparts (-19) - W = (-20) . Again , from - 19 a positive Jump imparts -19 + J = - 17 , a negative Jump from -19 imparts (-19) - J = (- 21) . Hence , the ' Count Exclusion ' process takes place when a positive Jump is made from - 19 to - 17 and the ' count excluded ' is - 18 . When negative Jump is made from '- 19' to '- 21' , the ' count excluded ' is '- 20 ' .

For , the integer 65 calculate the results of questions asked . QUESTION :
Perform a positive Walk from 65 . Then perform a positive Jump from value obtained in previous step . Calculate the ' count excluded ' between values imparted by W and J . Now , again make a positive Jump from result of third step .

What is the final result - (a) By how many Jump 'J's' is it far from value 65 - (b)
Option 1) (a) = 69 , (b) = 1
Option 2) (a) = 69 , (b) = 2