Logical Number Theory

Each alphabet is represented as a number as shown in the image above. So now you choose an arbitrary word and represent it in the form of numbers above and let P P be the product of these numbers.

Find the smallest three digit composite number which cannot take the value of P P for any arbitrary word.

Details And assumptions:

  • You can choose any word (whether it makes sense or not does not matter).

  • As an explicit example , if the word is n i h a r nihar , then P = 14 × 9 × 8 × 1 × 18 = 18144 P=14\times 9 \times 8 \times 1 \times 18 = 18144 .

  • This problem is original.


The answer is 106.

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2 solutions

Nihar Mahajan
Jun 22, 2015

We can have product of numbers from 1 1 to 26 26 .Note that if P P contains a prime which is greater than 26 26 , then it cannot represent any word. So lets start with 101 101 .

101 = p r i m e 102 = 17 × 2 × 3 = p o s s i b l e 103 = p r i m e 104 = 8 × 13 = p o s s i b l e 105 = 3 × 5 × 7 = p o s s i b l e 106 = 2 × 53 = n o t p o s s i b l e s i n c e 53 > 26 101= \ prime \\ 102 = 17 \times 2 \times 3 = \ possible \\ 103 = \ prime \\ 104 = 8\times 13 = \ possible \\ 105 = 3\times 5 \times 7 = \ possible \\ 106 = 2 \times 53 = \ not \ possible \ since \ 53>26

Hence 106 106 is the answer.

i did the same but is it mathematical valid?

Akash singh - 5 years, 9 months ago

101>26, therefore no combination of letters. I don't understand your arbitrary rule forcing 106.

Erica LaVoi - 5 years, 11 months ago

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Please read the rules properly , it states that we are in need of the smallest three digit "COMPOSITE" number and not prime.

Nihar Mahajan - 5 years, 11 months ago
Mukul Sharma
Jul 7, 2015

ITS SIMPLE; we just got to find a 3 digit composite number whose prime factorization involves atleast one prime no. that does'nt come between 1-26

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