Find the sum of 1 × 2 1 + 2 × 3 1 + 3 × 4 1 + 4 × 5 1 + 5 × 6 1 + … + 9 9 × 1 0 0 1
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The n t h term can be expressed as n ( n + 1 ) 1 = n 1 − n + 1 1 .So this is a telescoping series and it can be expressed as: 1 1 − 2 1 + 2 1 − 3 1 + ⋯ + 9 9 1 − 1 0 0 1 All the intermediate terms cancel and we are left with 1 − 1 0 0 1 = 0 . 9 9
1/2+1/6 = 3/6+1/6=4/6=2/3
2/3+ 1/12= 9/12=3/4
3/4+1/20= 16/20=4/5
Well that's the logical pattern
So answer will be 99/100 =0.99
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1/(1x2) = 1/1-1/2 ; 1/(2x3) = 1/2-1/3 ; 1/(3x4) = 1/3-1/4 and so on
1/1 -1/2+1/2-1/3+1/3-1/4+1/4 -1/5+1/5-1/6+...+1/98 -1/99+1/99 -1/100 = 1/1-1/100 = (100-1)/100
=99/100 = 0.99