Logically Easy Equation
If known as :
f(1) = 1;
f(3) = 11;
f(5) = 101;
f(16) = 10000; and
f(28) = x;
So what is
y
if
y
=
(x mod 28) + f((x mod 27)-1)
?
The answer is 22.
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1 solution
This problem is about binary equation so f(X) = to change X from base 10 to base 2.. in the question x = f(28). so we change 28 into base 2 and we got 11100. -> f(28) = 11100 = x. so we can get y = (11100 mod 28) + f((x mod 27) - 1) = 12 + f(3-1) = 12 + 10 = the answer -> y = 22