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Algebra Level 2

Calculate 2 log ⁡ 4 200 0 6 + 3 log ⁡ 5 200 0 6 \frac{2}{\log_42000^6}+\frac{3}{\log_52000^6}

1/6 2/3 2/6 5/4

Cid Moraes by Cid Moraes , 35, Brazil

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2 solutions

e x p = 2 ∗ log ⁡ 4 6 ( log ⁡ 2000 ) + 3 ∗ log ⁡ 5 6 ( log ⁡ 2000 ) e x p = 2 ∗ log ⁡ 4 + 3 ∗ log ⁡ 5 6 ( log ⁡ 2000 ) = log ⁡ ( 16 ∗ 125 ) 6 ( log ⁡ 2000 ) exp=\dfrac{2*\log4}{6(\log2000)} + \dfrac{3*\log5}{6(\log2000)} \\exp=\dfrac{2*\log4 +3*\log5}{6(\log2000)}=\dfrac{\log(16*125)}{6(\log2000)} \\~~~\\
= 1 6 \\=~~~~~~\boxed{ \color{#D61F06}{ \dfrac{1}{6} } }

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Very Nice! thank you

Cid Moraes - 6 years, 5 months ago

See the image for explaination

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