Logs

Calculus Level 1

Find x:

log 3 81 + log 2 32 = log x 512 \log _{ 3 }{ 81 } +\log _{ 2 }{ 32=\log _{ x }{ 512 } }


The answer is 2.

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2 solutions

Rocky El-Azar
Apr 25, 2014

l o g 3 ( 81 ) = 4 log_3(81) = 4

l o g 2 ( 32 ) = 5 log_2(32) = 5

l o g 3 ( 81 ) + l o g 2 ( 32 ) = 9 log_3(81) + log_2(32) = 9

l o g x ( 512 ) = 9 log_x(512) = 9

x 9 = 512 x^9=512

x = 2 x=2

no calculus involved

Ifunanya Nwogbaga - 6 years, 10 months ago
Muhammad Tir
Oct 10, 2014

I did this all without a calculator

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