LoL problem

Algebra Level 2

( 2012 ) ( 2015 ) ( 4029 ) + 2019 201 3 2 = ? {\frac{(2012)(2015)(4029) + 2019}{2013^{2}}} = \, ?


The answer is 4031.

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1 solution

Ashwin K
Feb 4, 2016

Looking at the problem we get scared. Not really.

For this type of problem, write it in a general way

Let n = 2013  //mostly denominator will be the required variable.

we rewrite it as ,

( n 1 ) ( n + 2 ) ( 2 n + 3 ) + ( n + 6 ) n 2 \frac{(n-1)*(n+2)*(2n+3) + (n+6)}{n^2}

Upon simplification, we get ,

2 n 3 + 5 n 2 n 6 + n + 6 n 2 \frac{2n^3 + 5n^2-n-6 + n + 6}{n^2} = 2n + 5.

Solution : 2 ( 2013 ) + 5 = 4031 \boxed{ 2(2013) + 5 =4031}

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