Long binary number

Number Theory Level 3

How many bits are required to store the result of $\large \ 20^{4^3} \times 52^{8^{2}}$ as binary number?

1 solution

Ossama Ismail
Jan 20, 2018

Ans: 642

Let $\large n = 20^{4^3} \times 52^{8^{2}} = 1040^{64}$

The number of bits requires to represent $n \ \text{is} \ \log_2 n = = 641.431= 642$ bits.