Longest straw

The hint to the answer is in fact already in the question. The word is pressure . We will derive a formula (because I hate quoting) for pressure based on the definition that: $P = \frac{Force}{Area}$ . So:

$P = \frac{Force}{Area} = \frac{F}{A} = \frac{F \cdot d}{A \cdot d}$

$= \frac{W}{V} = \frac{Energy}{Volume} = \frac{mgh}{m \rho} = \rho gh$

Rearranging, $h = \frac{P}{\rho g}$ . Now just chuck in the variables to get $h= \frac{101325}{9.8 \times 1000} = \fbox {10.34}$

We have to use the equation $P=\rho gh$ , where $P$ = pressure, $\rho$ = density in $kg/m^{3}$ , $g$ = acceleration of gravity = 9.8, and $h$ = height of water reached = length of the straw

We can easily find the answer by plugging the correct values into the formula, but take note that the density of water must be in in $kg/m^{3}$ , so we must convert $1g/cm^{3}$ to $1000kg/m^{3}$

* Therefore, $h = \frac{101325}{9.8\times1000} =10.339$ *

As the water column in the straw must have the same pressure as the water in the base of the straw (here we are going to suppose that the base is just touching the water), we have $\rho g h = p_{atm}$ , where $\rho$ is the density of the water, $h$ is what we are looking for and $p_{atm}$ is the ambient pressure. Solving for $h$ we have $h = \frac{p_{atm}}{\rho g} = \frac{101,325}{1000 \times 9.8} \approx 10.340 m$

P1 = ρ g h.

P2 = 1 atm (101,325 Pa).

P1 = P2.

ρ g h = 101,325

h = 101,325 / (ρ*g)

h = 101,325 / (1*9.8)

h = 10.340 meters.

P=pgh

Where P=pressure, p=density, g=gravity, h=height

h=P/pg

h=101300/(9.806*1000kg/m^3)

h=10.3m

We can drink from the straw as long as the pressure due to weight of the liquid column inside the straw doesn't exceed the atmospheric pressure. The condition for this is density g h = 101325 . Therefore h = 101325/(g*density) = 10.340m . Take density of water to be 1000kg/m3 .

You multiple the Pa, by gravity, and 1000 to get your answer

the trick was just to change the units regarding the density of water Solution: pressure=101325Pa density of water=1gm/cm^3 or 1000gm/m^3 acceleration due to gravity=9.8m/sec^2 height=h then we know about the liquid pressure formula pressure= height density of water acceleration due to gravity 101325/1000*9.8 = h h=10.34meter approx

the density of water is 1g/cm^3 to change in kg = 1000kg/m^3

h= atm/ pg h= 101325 / 1000 x 9.8 h= 101325 / 9800 h=10.3

the density of water is 1g/cm^3 to change in kg = 1000kg/m^3

101325 / 9.8 =10339.2
10339.2 / 1000 =10.3

The pressure due to the water in the straw is equal to the atmospheric pressure

i.e. ${{\rho}gh}_{water}={1atm}={101325}$

Thus ${h}=\frac{101325}{{\rho}g}$

and ${h}=\frac{101325}{1000\times9.8}$

so ${h}=\frac{101325}{9800}$

Hence ${h}=\boxed{10.3393m}$

data:- g+ 9.8 m/s2 p(rho)=density= 1 g/cm3 =1000kg/m3 1 atm= 101325 Pa h= height= ? solution:- we know that P=p(rho) g h therefore h= P/ p(rho) g putting the values in the derived equation h= 101325/ 1000 9.8 => 101325/9800 h= Height of the straw= 10.333= 10.34 m (Answer)

Luckily I remembered the formula Pressure=(density)(gravity)(height) so you just need to solve for height and take the water density as 1000 kg/m3

P=pgh

Where P=pressure, p=density, g=gravity, h=height

h=P/pg

h=101300/(9.806*1000kg/m^3)

h=10.3m