A normal soccer ball is in the shape of a truncated icosahedron. It has 12 pentagonal faces and 20 hexagonal faces. How many edges does it have?
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According to Euler's polyhedron formula, V − E + F = 2 . Notice that the truncated icosahedron does not have any pentagons that share a face nor does it have any vertices that are only surrounded by hexagons so the number of vertices is V = 1 2 ⋅ 5 = 6 0 . The number of faces is simply F = 1 2 + 2 0 = 3 2 . Then by Euler's polyhedron formula, 6 0 − E + 3 2 = 2 ⟹ E = 9 0 .